z^2(1-z^2)=16

Solution for z^2(1-z^2)=16 equation:

Simplifying
z2(1 + -1z2) = 16
(1 * z2 + -1z2 * z2) = 16
(1z2 + -1z4) = 16

Solving
1z2 + -1z4 = 16

Solving for variable 'z'.

Reorder the terms:
-16 + 1z2 + -1z4 = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + 1z2 + -1z4 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
16 + -1z2 + z4 = 0

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + -1z2 + -16 + z4 = 0 + -16

Reorder the terms:
16 + -16 + -1z2 + z4 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1z2 + z4 = 0 + -16
-1z2 + z4 = 0 + -16

Combine like terms: 0 + -16 = -16
-1z2 + z4 = -16

The z term is -1z2.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1z2 + 0.25 + z4 = -16 + 0.25

Reorder the terms:
0.25 + -1z2 + z4 = -16 + 0.25

Combine like terms: -16 + 0.25 = -15.75
0.25 + -1z2 + z4 = -15.75

Factor a perfect square on the left side:
(z2 + -0.5)(z2 + -0.5) = -15.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.